Do you like maths?
might be a good idea to link the picture of the problem.
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Maybe you should do your own work, or use any of the countless resources available on the Internet, or ask your teacher tomorrow.
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apparently, from what I have heard its due tommorow
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Perhaps he should have planned ahead and sought help before his deadline. It's a pity that he messed up, but academic dishonesty only cheats one out of a proper education.
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Maybe, just maybe, the last thing on my mind is to "cheat" because I am looking to score high on my exams, I am just saying, maybe.
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Then you should seek better alternatives to having others do the work for you.
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You stupid? I don't want ANYONE TO DO IT FOR ME. I want them to EXPLAIN the METHOD. Does that make a lot more sense?
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I wouldn't consider myself stupid when you're the one who failed to make that clear. The initial thread post only asked for help, but usually "help" on one's homework equates to solving the problems for them. Perhaps in the future you should be clearer in your requests.
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Should have said that and I would have fixed it. Instead, what you did was make assumptions, something I believe no one should ever do.
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Given the prevalence of individuals asking for others to do their homework for them, coupled with the lack of clarity in the original post, it's not that surprising that I would make assumptions.
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You have a point, I see where you are coming from but I would still say making assumptions is something you should not do, it would have been better for you to ask "are you looking for someone to help do you work?" or something along the lines of that.
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↑↑↑
Nokkenbuer seems to be a fearsome politician in steamgift
he gave a wise answer
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Only god knows... Or the universe, depending on what you believe in....
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Maybe I am not looking for someone to do the work for me? and just maybe the resources I am looking for can not be found on the internet? Maybe I have talked to my teacher but she is of no help? and just maybe I have gone and asked another teacher from the maths department but they were not able to help but are willing to later on another day?
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I seriously doubt there are no resources on the Internet, let alone your own math teacher, can't help you. Unless there was a reason why your teacher wouldn't, I find it difficult to believe that would be the case.
Perhaps you could ask friends or acquaintances, or family members who you suspect would know how to help you.
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Let me explain, I can find stuff on the DISCRIMINANT but not on USING THE DISCRIMINANT + QUADRATIC INEQUATIONS. My math teacher thinks we have all done what her class has done last year, she didn't even explain it properly. My peers are also struggling to get through this. The teacher I talked to was on duty and was willing to help but during his class which is at the end of the day while my other class is at the start. My family can't help as they have no idea what it is. Most of my peers don't have any way of communicating with me.
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Sorry that you're in such an unfortunate predicament. My only other suggestion would be to ask your math teacher again and request that she help you. If she tries to deflect or dismiss the issue, correct her that you nevertheless don't understand and would like for her to help because her instructions were unclear to you.
The following links are some information I could find on the topic of using the discriminant in quadratic inequalities:
[AnalyzeMath.com] Quadratic Inequalities
[LTCConline.net] Quadratic Inequalities
[WikiHow.com] How to Solve Quadratic Inequalities
[Brightstorm.com] The Discriminant of a Quadratic Equation - Concept - Algebra 2 Video by Brightstorm [VIDEO]
[Alegbra.com] Lesson Solving quadratic inequalities
[MathematicsMagazine.com] Best Methods for Solving Quadratic Inequalities [PDF]
[YouTube.com] Using the Discriminant for Quadratic Equations [VIDEO]
[MathWiki@UCDavis.edu] Quadratic Inequalities - MathWiki
[ClassZone.com] EXAMPLES Using the Discriminant - Quadratic Equations and Functions [PDF] (Algebra 2, p. 556)
Hope that helps.
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Would have been checkmate if I was playing chess but unfortunately I have no interest in such a thing.
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Thanks for that, the problem with looking for help on the internet is that it introduces more questions than answer in most cases. For example it may be asking you to use a method you are not familiar with which would be due to the fact that you are not meant to have learnt it for your age or something along the lines of that. I will have a look at them, especially the videos, you have my utmost gratitude for helping me in this regard.
The other day asked her if square root 6 is the same as square root 3 x square root 2 and therefore due to square root 2 being irrational square root 6 would be too, she stared at me blankly and walked off.
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Some of the links are more difficult to understand than others, so be sure to check them all.
Your teacher is an idiot. Technically, square root(6) can be argued as both rational and irrational, but from what I've read square root(6) is usually considered irrational by virtue of contradiction. In other words, square root(6) is irrational, not rational.
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Yeah I have seen that proof and done it too, Euclids proof of square root 2? Cant spell his name xD
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Fun Fact: It's believed that the proof by infinite descent (or by contradiction) of the irrationality of square root(2) is an interpolation and not an attribution. Although commonly associated with the Ancient Greek geometer Euclid of Alexandria, it was probably a misattribution on Aristotle's part.
But yes, the irrationality of square root(2) is definitely an interesting phenomenon in mathematics.
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Why do you assume his teacher is a she and not a he?
just wondering...
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".....thinks we have all done what her class has done last year, she didn't even explain it properly." Just quoting what I said..
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Is this the stuff you need?
http://www.analyzemath.com/Inequalities_Polynomial/quadratic_inequalities.html
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Bless you, no idea what polynomials are but this seems to be it! THANKS MATE! I WILL THOROUGHLY READ IT!
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A polynomial is an expression of two or more algebraic terms. It comes from the Latin prefix "poly-" meaning many and the Greek word "nomós" meaning (in this context) part or portion. Basically, it's just "many parts." A monomial pretty much is just an algebraic term and more specifically a polynomial with one term (hence "mono-"); a binomial is a polynomial with two terms (hence "bi-"), a trinomial is a polynomial with three terms (hence "tri-"). Although there could technically be more, such as "quadrinomial," usually algebraic expressions past three terms are considered just polynomials.
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actually spent some time as a math tutor cause I like this stuff :-) But a quick browsing seems to show you already found help... so... good luck :)
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Just calculate delta. (AKA discriminant)
delta = b^2 - 4 a c;
if (delta == 0) sol = 1;
if (delta < 0) sol = 0;
if (delta > 0) sol = 2;
done.
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For the sake of clarity I'd add that if delta < 0 you could actually find solutions in the complex numbers domain.
If the OP doesn't know what complex numbers are, disregard this message.
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Complex number is a number which is in part Real and in part imaginary. At least I hope that it is called imaginary in English (I always learned math in Polish - if I messed up something in translation someone will probably tell you the correct term)
Now think of this - how to calculate something using imaginary numbers... To be honest it is much simpler than how it sounds right now.
And here is the very important thing - the only language which computers understand is math. We all use sophisticated languages to it to make it more human friendly - but in the end - it is only mathematics. So if you want to create games, hack games or maybe just figure out how enemy AI works - learn math.
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hey, hey, no discriminating Delta, he's a nice guy!
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Thanks, I have watched it, didn't get anything out of it because I know all of it.
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well, knowing is not what you want.
you need to understand the concept, then you can solve all calculations of that class
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Its simple,
Imaginary roots (mo real root) always occur in pairs.
So these cases are possible:
- Both roots imaginary
- Both roots real and different
- Both roots are same, meaning only 1 root.3
Ok now to the equation itself.
Lets say your equation is aX^2 + bX + C = 0
Then D = sqrt(b^2 - 4ac)
When D=0, you get 1 root, ie both roots are same
When D>0, you get two real roots
When D<0, you get two imaginary roots, ie not real
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I never understood this in middle school. I'm in college upper level statistics courses now and I still don't get this. ^
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Em.. It's really sad :( May be you'll understand after this image? It's the transformed equation ax^2+bx+c=0. You can check that they are equal. After taking square root from that equation and moving non-x part to the right, you'll get the answer for x. This leads to all the consequences with the number of roots.
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Oh I figured it out. These are just tricky ways of trying to explain algebra. Still I hate how the teachers always taught you to memorize rules instead of producing an intuitive understanding of the operations and their outcomes.
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https://www.khanacademy.org/math/algebra/quadratics/quadratic-formula/v/using-the-quadratic-formula
Khan Academy has some good explanations in video form, and practice/test questions for all levels of maths (except super hard beyond undergraduate university maths I think).
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hm...stops at the stuff i had in the first/second semester math at the university. but seems to be nice for people starting some STEM related study :)
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I didn't look very hard - I saw the post before work. Could be more if you looked around on the site, but you're right - I don't know how high the difficulty really goes.
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all I can say to this...
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I am stuck on my maths work and I really really need some help! Its do with quadratic inequalities. So basically I need to find when a certain quadratics discriminant will have 1 sol, 2 and none. If any of you are willing to kindly donate some time towards helping a poor dude with some math, please add me!
I just need the method explained and not for you to do my work.
Thanks!
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