Russell's paradox: Let R be the set of all sets that are not members of themselves. If R is not a member of itself, then its definition dictates that it must contain itself, and if it contains itself, then it contradicts its own definition as the set of all sets that are not members of themselves.
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Thanks for this giveaway!
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do that paradox have an equation?
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I doubt it. I can't think of a way to represent it as an equation.
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This comment was deleted 4 years ago.
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Math abstraction always surprised me. And here i'm struggling with tensor analysis.
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That's not an equation though
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This comment was deleted 4 years ago.
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Thank you so much:))
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Thank You
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It's funny, the first time I heard Russell's paradox was in Runescape, namely that if an armour set contained all armour sets, did it contain itself
I also like Theseus' ship; If you replace any individual part of a ship, it is the same ship. So if you proceed and replace all of them, one by one, it is still the same ship. If you then take all the original parts and assemble them together, you have the original ship too.
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Never could get my head around this type of math. But enjoyed entering the above game. Bump
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I prefer the barber paradox example rather than the formal description:
The barber is the "one who shaves all those, and those only, who do not shave themselves." The question is, does the barber shave himself?
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Self-reference leads to all kinds of paradoxes.
I strongly recommend the great book Gödel, Escher, Bach: An Eternal Golden Braid to anyone who is intrigued by such things.
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Thanks for the gift Rupti!
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