Description

For the third giveaway you need this: 101 4 193 107 70.

BUMP

Well, the code help. :)

7 years ago
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Here i am again :)

Took me a while until i realised it has to be

if (sum1[c]=sum1[c+1]) and (sum1[c]= sum1[c+2]) then

to get the triplets, not the doubles. Wondered why i got so many results before^^

7 years ago
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do you also had the problem that there were more then 3 combinations

7 years ago
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yeah. But turns out the one with the most combinations is the right one...so you only have to rule out those which are somehow double or use a number twice.

7 years ago
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Yep, it throws off my otherwise nice Python script. Same with the second puzzle.

7 years ago
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Thanks for a gift!

7 years ago
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