There are 100 prisoners lining up to go to jail. Each prisoner is wearing a hat that is either black or white. The prisoners don't know their own hat color, just the hat color of those in front of them in line (the first prisoner in line can't see anyone's hat and the last prisoner can see everyone's hat except their own). Starting from the back, one of the guards asks each prisoner what color their hat is. If they are correct they get to go free but if they are wrong they go to jail.If the prisoners get to discuss a plan, how can at least 99 of them be saved?
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thanks
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Thank You!
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The prisoner at the very back tells the other 99 the color of their hats. Or am I missing something?
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they can only say black or white and only one time
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They gang up and kill the guards! Thank you!
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thank you!
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Everyone can ask the prisoner behind them which color is his hat, and then the last one by elimination will know which color is his
or maybe they cant ask that?
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they can only say black or white and they're are not allowed to speak and touch each other while lining up.
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The prisoners tell the person infront of them the colour of their hat. The person at the back has a 50% chance of calling out the correct colour. Maybe slightly higher since he can see a pattern if there is one.
Edit: The guy at the back breaks the rules and tells everyone else.
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they can only say black or white one time and they're are not allowed to speak and touch each other while lining up.
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Thank you, Xerath! :)
Hmm, I'm half-asleep and my tired head is stumped by this hat conundrum. ;)
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Thank you! :)
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i'm terrible with these questions...
hi and thanks riddler!
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Thanks !
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The last prisioner says what colour is the hat in front of him... that way the man in front of him knows the colour of their hat... 99 saved and the first who spoke have 50% chance to be saved too... is that the solution???? thanks for the giveaway sorry for my bad english.... im portuguese
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nop. they can only say black or white one time and they're are not allowed to speak and touch each other while lining up.
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The back prisoner will yell "black" if there is an odd number of black hats in front of him and "white" if there is an even number of black hats in front of him. The next prisoner will then count the number of black hats in front of him and if it was odd and is now even, or vice versa, then that person knows what color their hat is. The next person then knows their hat color based on what the people before them said and how many black hats are in front of them. In this way the front 99 prisoners will know their hat color and will be set free. The prisoner in the back who goes first has a 50 percent chance of being set free. (I used google cuz too lazy)
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Didn't use Google, but this is right.
My dad told me this riddle a while ago. :)
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Thanks You (๑ ั็็ั ั็ ั็็ั ั็•็ั ั็็ั ั็็ั ั็ ั็็ั﹏ ั็็ั ั็ ั็็ั ั็•็ั ั็็ั ั็ ั็็ั ั็ ั็็ั๑)
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Thank you!
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I think I have heard about this...
The 100 person need the said "black" if they see odd number of black hats and ":white" if they see even number of black hats in front of him
Then the rest of them will be able to deduce it? xD
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Thanks :)
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Thx
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Shit man, I know the answer but I'm too lazy to type it. Basically black and white, 50/50 chance
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Graciatos Maciatos
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tnx
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Thank you!
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Thanks
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the last prisoner tells the guard that whatever they say is a lie... xD
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Isn't it impossible to know what you would/should do unless you are actually in the position?
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